00-µF capacitor when connected to a 12.0-V battery.
Given:
Capacitance (C) = 4.00 µF = 4.00 x 10^-6 F
Potential difference (V) = 12.0 V
Use the formula Q = C * V to calculate the charge:
Q = 4.00 x 10^-6 F * 12.0 V
Q = 48.00 x 10^-6 C
Q = 48.00 µC
Therefore, the
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