00:02
So in this problem, we have a high hydraulic lift, and we are told that the narrow cylinder in our lift has a diameter, which i'll know to know as d1 equal to 4 centimeters, which when converted to meters is equal to 0 .0 meters.
00:26
And our wide cylinder has a diameter d2 equal to 30 centimeters, which one converted is equal to 0 .3 meters.
00:44
And so let's create a rough sketch of what's going on.
00:49
So we have our narrow cylinder over here, and we have a hydraulic lift in which we have our wide cylinder from this side.
01:02
So i'll say that this is our, where we have our diameter one, and this is where we have our diameter two.
01:10
And so we're asked to calculate the force that must be applied.
01:20
So calculate force required, essentially required to push liquid in our small cylinder.
01:42
And so when we draw the direction of this force, it will look something like this.
01:47
So i'll say that this is a value f.
01:50
And so we have a force pushing down where our small cylinder is.
01:55
And we're going to have, we are told that a car, which will denote as just a simple, a simple sketch here.
02:06
And so suppose that we have a car over here, and our car has a mass, which is equal to 1 ,000.
02:15
500 kilograms.
02:17
So what force do we need to push our car of 500 kilograms? so using our equation for pressure, we can set the pressures equal to each other...