A hydraulic lift has pistons with diameters 8.10 cm and 37.0 cm, respectively. If a force of 825 N is exerted at the input (smaller) piston, what maximum mass can be lifted at the output piston?
Added by Elizabeth S.
Step 1
For the smaller piston: Radius (r) = 8.10 cm / 2 = 4.05 cm Area (A1) = π(4.05)^2 = 51.47 cm^2 For the larger piston: Radius (r) = 37.0 cm / 2 = 18.5 cm Area (A2) = π(18.5)^2 = 1075.29 cm^2 Show more…
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