00:01
To determine the ph of the buffer solution we can use the henderson -hasselbalch equation.
00:06
Ph will be equal to pka, which is the negative log of the ka value for the acid in the buffer.
00:15
The acid is the ammonium.
00:19
The kb for ammonia is provided, so ka will be kw, 1 .0 times 10 to the negative 14 divided by kb, 1 .76 times 10 to the negative 5.
00:36
So again pka is kb divided into kw.
00:42
That gives us ka.
00:44
We take the negative log of that to get pka.
00:47
The rest of the henderson -hasselbalch equation is plus the log of the concentration of the base over the concentration of the acid.
00:57
They tell us we have a 100 milliliter buffer.
01:00
That is 0 .02 molar in the base and 0 .035 molar in the acid.
01:14
And we get an initial ph of 9 .00.
01:21
Then to determine the ph after the addition of the hcl, we recognize that every mole of hcl will have a hydronium ion that reacts with the ammonia producing more of the base, sorry, more of the acid, ammonium, and water.
01:42
So ph can be calculated still using the henderson -hasselbalch equation.
01:47
As long as we don't add more hcl than we have of ammonia, that'll be equal to pka, which again will be the negative log of the ka value for ammonium...