00:01
In this problem, we have been given that there is a gas present in the container which occupies a volume of 13 liter and the number of gas present is 1 mole and provided that the pressure of the gas contained in this container, that's one atmosphere.
00:25
And we need to determine the temperature of the gas in kelvin's.
00:30
So for this, we're going to make use of the gas equation, which is pv is equal to nrt.
00:38
R is the real gas constant.
00:40
And from here, we just put the values of the variables that we have but in the si unit.
00:46
So the volume needs to be converted into cubic meters.
00:50
So that will be 13 into 10 raise to minus 3 cubic meter.
00:56
And atmosphere, we know that 1 atm is 1 .01 into 10 raise to 5.
01:03
Pascal's.
01:04
So if you put the values here, we get 1 .01 into 10 raised to 5 times 13 into 10 to minus 3.
01:11
That's equal to 1 into 8 .314.
01:15
That's the value of r times the temperature.
01:19
So from here, if we solve, we're going to get t as 1 .01 into 13 into 10 raised to 2 divided by 8 .314.
01:29
So let's simplify the numerator first.
01:32
So when we multiply 1 .01 with 13 and 100 is multiplied, we divide it by 8 .314, we get the temperature as 157 .93 kelvin.
01:48
So that's the temperature of this case in kelvin.
01:54
And in the next situation, we have been given that the same container that's fitted with a piston which can slide and the volume can definitely change because of the slide.
02:08
Now it's given that the gas if it is heated at constant pressure.
02:14
So the pressure is kept constant here.
02:17
It is observed that the gas expands to a volume which is 27 liters.
02:25
So earlier it was 13 liter and the gas expands on heating to 27 liters.
02:31
So we need to determine.
02:32
The temperature of gas in kelvin's...