In a reactor, 483 mol of CH4 and air are fed in excess. The reaction taking place is: 2CH4 + 7O2 -> 6CO2 + 8H2O. Calculate the amount of moles of air fed for a 20% excess.
b) For a 60% conversion of the limiting reactant of the previous problem, the one where you calculated the moles of air in excess, calculate (by any method you choose) the composition (y) at the exit of the reactor. Please put all procedures.