A in an open vessel at a constant atmoshphere b in a closed...

a) in an open vessel at a constant atmoshphere, b )in a closed vessel at a constant volume, which of the following is false? 1. in a closed vessel we are unable to disiguish between enthalpy change and work peformed (+-w) numerically: therfore, we can only calculate total enegery, chang in e, 2. if the same amount of external energy is supplied to each, the closed vessel will report a higeher tempature increase than reported by the vessel 3. coffee cup calorimeter is an open system while a bomb comlometer is a closed system. 4 in an open vessel system, the tempature chnage helps calculate the enthaly change while the volume change helps calculate work performed5. a gas reaction mixture inside a tighly sealed rubber balloon is an exmaple of a closed system if there is np openejing in that conatiner for air to escape

Transcript

00:01 Basically here in this question we have to choose the correct answer for the given questions.

00:05 So in the first part of the question or the a part we are given that heat is flowing into the system which is containing a fixed mass of the gas.

00:12 The system boundary is given which is rigid.

00:15 So we are given the four statements and out of that four statements we have to choose which statement is correct.

00:21 So first statement is given that if internal energy remains constant then enthalpy increases.

00:28 So first statement is incorrect.

00:32 If internal energy is constant so it is given that the enthalpy increases.

00:41 So this is not the case.

00:43 Hence the statement one is incorrect.

00:45 Statement two is given which is that if the enthalpy increases then internal energy also increases.

00:56 So this statement is correct that if the enthalpy increases then internal energy also increases.

01:07 Let's discuss how.

01:08 Let's say dh is equal to du plus d multiplied by the pv.

01:13 So dh from here becomes equal to du plus p multiplied by the dv plus v multiplied by the dv.

01:19 Here as v is constant so we can say that dv here in this case becomes equal to zero.

01:26 Then we are only left with that dh is equal to du plus v multiplied by the dp.

01:32 So in a constant volume heat addition process all the heat added is converted into the internal energy.

01:38 Hence internal energy increases.

01:41 Since dh is equal to du plus vdp where dp is given which is a positive means with the increase in temperature pressure also increases when volume is constant.

01:52 Therefore enthalpy increases.

01:54 Hence option b is correct.

01:55 Option c is given that enthalpy remains constant and external energy external energy increase.

02:07 So this is also not the case according to the given statement.

02:11 Fourth is given that internal energy remains constant then enthalpy remains constant.

02:22 So this too is incorrect statement according to the given relation.

02:28 Hence the answer to the first is part 2.

02:31 Now we are considering about the b which properties kinematic.

02:36 So we have to discuss the kinematic properties.

02:38 First is given that is volume.

02:40 Second is given which is density.

02:43 Third is given which is time and the fourth is given which is stress.

02:48 So we have to discuss about the kinematic property.

02:52 So from all the property density is volume is not the kinematic because volume is basically the area which is processed by any gas or anything over the space in three dimension.

03:06 So density yes density is a kinematic property because density is equals to dynamic viscosity...

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