Question

a) In J. J. Thomson's experiment (1897), an electron moving horizontally with a constant speed vo enters between the horizontal plates of a capacitor. The electric field strength between the plates of length L and distance d is E. The vertical deviation of the electron at the moment of exit from the field region is measured to be Y. Derive the expression giving the electron's charge-to-mass ratio, i.e. e/m, to be 2v^2Y/(EL^2). (Recall that Thomson received the Nobel Prize for his achievement.) b) Calculate e/m, knowing the following data: E = 1.6x10^4 Newton/Coulomb, L = 10 cm, Y = 2.9 cm, v = 2.19x10^5 km/s. (Be careful to use coherent units.)

          a) In J. J. Thomson's experiment (1897), an electron moving horizontally with a constant speed vo enters between the horizontal plates of a capacitor. The electric field strength between the plates of length L and distance d is E. The vertical deviation of the electron at the moment of exit from the field region is measured to be Y. Derive the expression giving the electron's charge-to-mass ratio, i.e. e/m, to be 2v^2Y/(EL^2). (Recall that Thomson received the Nobel Prize for his achievement.)
b) Calculate e/m, knowing the following data: E = 1.6x10^4 Newton/Coulomb, L = 10 cm, Y = 2.9 cm, v = 2.19x10^5 km/s. (Be careful to use coherent units.)

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