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Hello student.
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In this question, a equation is given that is h.
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So4 minus in the aqua solution is reacting with oh minus present in aqua solution and it is giving s .o .2 minus again in aquaise solution plus h2o, which is liquid in this solution.
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Now we have to say which one is the bronch state acid and which one is the bronzed base.
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Now according to the bronze -state -lowry acid -based theory, bronstate -lowdy acid are those which can donate h -plus ion.
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So here the h -s -o -4 -minus can donate a proton, that means h -plus it can give, so it will give a h -plus and it will form a s -o -4.
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To minus so we can say that this is the bronzed bronzed lorry acid and the bonstead lorry acid forms of conjugate base so the s .o4 to minus will be the conjugate conjugate base.
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Now moving to the next one, bronstead -lowdy base is one which can accept a h -plus.
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So here, o -h -minus will accept h -plus to form the h -2 -o.
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So it will accept h -plus.
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So we can say that this is the bronstate -lowdy base and the h -2 -o which is forming is the conjugate acid.
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Conjugate acid.
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So this is the answer for the first part.
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Moving to the next one, we can say that a.....