(a) Ka for HNO2 is 4.6 x 10-4 . What is the Kb for its conjugate base ? (b) Calculate the pH of 0.1 M of HNO2 solution above.
Added by Elena G.
Step 1
Given Ka for HNO2 = 4.6 x 10^-4 Kw = 1.0 x 10^-14 Kw = Ka * Kb Kb = Kw / Ka Kb = (1.0 x 10^-14) / (4.6 x 10^-4) Kb = 2.17 x 10^-11 Show more…
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