A laboratory technician is to be tested on identifying blood types from 9 standard classifications. Complete parts (A) and (B) below. (A) If 4 distinct samples are chosen at random from the 9 types and if the technician is not allowed to repeat any answers, what is the probability that all 4 could be correctly identified by just guessing? Let the sample space S be the set of ways that the 4 distinct samples can be chosen from the 9 standard classifications. The number of elements in the sample space S is n(S) = [ ]. (Type a whole number.) The probability is [ ]. (Type an integer or a simplified fraction.) (B) If repeats are allowed in the 4 blood types chosen at random from the 9 and if the technician is allowed to repeat answers, what is the probability that all 4 are identified correctly by just guessing? The probability is [ ]. (Type an integer or a simplified fraction.) In a lottery game, a single ball is drawn at random from a container that contains 25 identical balls numbered from 1 through 25. Find the probability that the number drawn is even or a multiple of 9. The probability that the number drawn is even or a multiple of 9 is [ ]. (Type an integer or a decimal.) A shipment of 40 inexpensive digital watches, including 9 that are defective, is sent to a department store. The receiving department selects 10 at random for testing and rejects the whole shipment if 1 or more in the sample are found defective. What is the probability that the shipment will be rejected? The probability the shipment will be rejected is [ ]. (Simplify your answer. Type an integer or decimal rounded to two decimal places as needed.) Find the conditional probability, in a single roll of two fair 6-sided dice, that the sum is greater than 7, given that neither die is a four. The probability is [ ]. (Type an integer or a simplified fraction.)
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So, n(S) = C(9, 4) = 9! / [4!(9-4)!] = 126. The probability of guessing all 4 correctly is 1/126 because there is only one correct combination out of 126 possible combinations. (B) If repeats are allowed, then each of the 4 guesses is independent and has a 1/9 Show more…
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