00:01
Hello everyone and welcome.
00:03
This is a question regarding statistics and we want to see what the lowest score a new hire must earn in order to qualify for a position that is normally distributed with the mean of 500 and a standard deviation of 50.
00:18
And he has to be in the upper 6 % of the distribution.
00:24
So yeah, there's a lot of statistics involved in this question.
00:27
The first thing we have to do is make our normal model.
00:30
So we have x.
00:31
And remodeling it with a normal model, normal distribution, where the mean is 500, and the standard deviation is 50.
00:48
Right, so this was all given to us in the question itself.
00:53
And then we now we have to find the critical value.
00:56
And we're already to find the critical value in our standard normal table, we first have to see what probability we're looking at.
01:04
Because you see if this is our curve right over here, then 6 % is something like here.
01:11
We want all of this stuff.
01:13
So this is going to be 1 minus 0 .06, which is 94%.
01:18
So 0 .94.
01:21
So when we look at up 0 .94 in the standard normal table, we get that our critical value is equal to 0 .548.
01:35
So we've got 1 .5548...