00:01
Hello everyone.
00:03
So in this question for given 24 random sample data points of professional employees, we have to find the null and alternative hypothesis, the t -critical value, test critical value.
00:23
Further, we have to find the test statistics and then find the conclusion.
00:29
So as per the given information, the xi values are given where xi is the value of hours per month of various employees where the values of i range from 1 to 24.
01:01
The total n that is 24 employees data given.
01:07
So first we find the value of summation xi that is sum of all the 24 data points which will be equals to 399.
01:18
Now we calculate mean and standard deviation.
01:21
So mean which is x bar will be equals to summation xi divided by n.
01:30
So substituting the values here, we have summation xi is 399 divided by n which is 24 which will be equals to 16 .625 approximately.
01:43
Talking about standard deviation, standard deviation s is equals to square root summation xi minus x bar whole square divided by n minus 1 summation over i where the values of i range from 1 to 24.
02:07
Now substituting all the values, we have the value of x bar and in the question we have 24 values of xi, i from 1 to 24.
02:15
So this becomes square root summation xi minus x bar whole square will be approximately 113 .625 divided by n minus 1 that is 23 which in solving is approximately equals to 2 .2227.
02:41
Now coming to part a of the question, we have to state null and alternative hypothesis.
02:49
So professional employees will be volunteer on average of more than 15 hours per month in engaging during local service activities.
02:59
So the null hypothesis becomes h0 such that mu is less than equals to 15 which is tested against the alternative hypothesis ha such that mu is greater than 15...