a large tank is filled with methane gas at a concentration of 0770 kgm3 the valve of a 130 m pip

First, we need to understand that the rate of diffusion is given by Fick's first law, which stat

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A large tank is filled with methane gas at a concentration of 0.770 kg/m³. The valve of a 1.30 m pipe connecting the tank to the atmosphere is inadvertently left open for 11.0 hours. During this time, 6.90x10⁻⁴ kg of methane diffuses out of the tank, leaving the concentration of methane in the tank essentially unchanged. The diffusion constant for methane in air is 2.10x10⁻⁵ m²/s. What is the cross-sectional area of the pipe? Assume that the concentration of methane in the atmosphere is zero.

          A large tank is filled with methane gas at a concentration of 0.770 kg/m³. The valve of a 1.30 m pipe connecting the tank to the atmosphere is inadvertently left open for 11.0 hours. During this time, 6.90x10⁻⁴ kg of methane diffuses out of the tank, leaving the concentration of methane in the tank essentially unchanged. The diffusion constant for methane in air is 2.10x10⁻⁵ m²/s. What is the cross-sectional area of the pipe? Assume that the concentration of methane in the atmosphere is zero.

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