00:01
Hi, so we are given that a laser beam enters with the thickness 13 .5 cm a thick glass window at an angle of let's say theta is equal to 63 .0 degrees from the normal.
00:25
The index of refraction of the glass means refractive index mu is 1 .44.
00:35
So at what angle from the normal does the beam travels throughout the glass is we had to find out here.
00:42
So let's get started with solution.
00:46
First of all let's have a look to the concept which we were going to use will be the snell's law.
00:54
So according to snell's law we know that n1 sin i this should be equals to n2 sin r where i incident angle, r refraction angle, n1, n2 are the refractive indices for two medias.
01:15
So according to the question if you see that the incident angle we have been given 63 .0 degrees while n2 is equals to 1 .44.
01:30
So n1 should be equals to 1 because it should be an error here.
01:35
Substituting the values in our formula we get the refraction angle.
01:43
So this will become 1 into sin of 63 degree.
01:48
This should be equals to 1 .44 times of sin of r.
01:54
So after simplifying and solving for the value of r you will get the refraction angle as 34 .8 degree.
02:07
So we can say this is what one of the answer for question that is angle of refraction 38 .8 degree.
02:15
Now next thing we just have to compute that thickness here means for this much of angle of refraction what should be the thickness...