A laser with a power of 1.0 mW has a beam radius of 1.0 mm. What is the peak value of the electric field in that beam
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Step 1
0 mW = 0.001 W) and A is the area of the beam, which can be approximated as a circle with radius r = 1.0 mm: A = πr^2 = π(0.001 m)^2 = 3.14 x 10^-6 m^2 Therefore, the intensity is: I = 0.001 W / 3.14 x 10^-6 m^2 = 318.5 W/m^2 Show more…
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