Question

A lens located in the y-z plane at x = 0 forms an image of an arrow at x = x2 = 106.4 cm. The tip of the object arrow is located at (x,y) = (x1, y1) = (-57.3 cm, 4.95 cm). The index of refraction of the lens is n = 1.37. (1)What is f_lens, the focal length of the lens? If the lens is converging f_lens is positive. If the lens is diverging, f_lens is negative.

          A lens located in the y-z plane at x = 0 forms an image of an arrow at x = x2 = 106.4 cm. The tip of the object arrow is located at (x,y) = (x1, y1) = (-57.3 cm, 4.95 cm). The index of refraction of the lens is n = 1.37.

(1)What is f_lens, the focal length of the lens? If the lens is converging f_lens is positive. If the lens is diverging, f_lens is negative.

$A lens located in the y-z plane at x = 0 forms an image of an arrow at x = x2 = 106.4 cm. The tip of the object arrow is located at (x,y) = (x1, y1) = (-57.3 cm, 4.95 cm). The index of refraction of the lens is n = 1.37. (1)What is flens, the focal length of the lens? If the lens is converging flens is positive. If the lens is diverging, flens is negative.$

Added by Logan E.

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