00:01
All right, so we have a fiber optic cable with a cladding layer, which i'll draw here, which is shielding a cord layer underneath this.
00:12
And then above that, we have air.
00:15
And we're told that a ray escapes the cladding and makes an angle of five degrees with basically the axis of the cable.
00:23
So this is like an 85 degree refraction angle.
00:26
And the index of a fraction of the cladding material is 1 .2.
00:31
For the core, it's 1 .4.
00:33
And so we want to find out what angle did this originally make in the core area relative to, i guess, the axis of, relative to the axis of the cable.
00:49
So let's first off figure out what this angle is in the cladding.
00:53
We'll call this cl, theta cl.
00:56
And so we can use snell's law, so we have like the sign of 85 degrees times the index of a fraction of air, which is just one, is going to be 1 .2 times the sign of theta c .l.
01:08
And so if we solve for theta cl, we get something like 56 .12 degrees.
01:18
And we also have that, you know, this angle is also theta cl...