00:01
The charge of the line charge q is equals to lambda l which is equals to 2 .75 multiplied by 10 to the power minus 6 coulomb per meter multiplied by 0 .588 meter.
00:29
On calculating we will get 1 .617 multiplied by 10 to the power minus 6 coulomb and the electric field intensity due to line charge along its axis e1 is equals to k multiplied by q divided by xp multiplied by xp minus l putting the values 8 .99 multiplied by 10 to the power 9 multiplied by 1 .617 multiplied by 10 to the power minus 6 divided by 11 .5 multiplied by 11 .5 minus 0 .588.
01:37
On solving this we will get our answer 114 .68 newton per coulomb along the positive x axis so e1 will be equals to 114 .68 newton per coulomb.
02:08
So this is the final answer for the part 1 of the question.
02:15
Now moving further the electric field intensity due to the point charge is e2 equals to k multiplied by q divided by under root of xp minus x0 the whole square plus y0 square whole under root whole square.
02:52
On putting the values we will obtain 8 .99 multiplied by 10 to the power 9 multiplied by 6 .22 multiplied by 10 to the power minus 7 divided by under root of 11 .5 minus 1 .14 the whole square plus 4 .75 the whole square the whole square.
03:43
On solving this we will obtain value 43 .04 newton per coulomb.
03:51
This is the value for e2.
03:55
So now theta is equals to tan inverse of y0 divided by xp minus y0 which is equals to tan inverse of 4 .75 divided by 11 .5 minus 1 .14...