00:01
So density is 1210, right? and then we have location known.
00:10
So i'm going to call that v1, 9 .95 meters per second.
00:16
And diameter 1 is 12 .9 centimeters, where v2 is known, but diameter 2 is 16 .5 centimeters.
00:28
And location 2, let's call that height 2, is 9 .79 meters, right? we need to find the difference between the fluid pressure at location 2 and that at location 1.
00:43
So therefore, from the equation of continuity, we can say that area 1, v1 should be equal to area 2, v2.
00:51
So in other words, pi d1 over 4 multiplied by v1 should be able to give you pi d2 squared, or squared, either, 4 multiplied by v2, correct? in other words, we're trying to say that d1 squared v1 must be equal to d2 squared v2.
01:17
So d1 squared, therefore, is quite interesting here, right? we just key in these values.
01:26
12 .9 into 10 to minus 2, a square root, multiplied by the velocity 1, which is 9 .95 meters per second, should be equal to d2, 16 .5 into 10 to minus 2 squared, multiplied by v2...