00:01
Hello students, let's begin with this question.
00:03
In this question, this combustion reaction of propane is given and delta h for this reaction is given which is equals to minus 2044 kilojoule and in this question we have to find out the amount of heat released.
00:26
So, here we have to find out this q value.
00:32
So, in the question the mass of the liquid propane is also given which is equals to 13 .2 kg.
00:41
So, 1 kg is equals to 1000 gram.
00:46
So, this comes to be 13200 gram.
00:51
So, firstly here formula used is, so this q is equals to delta h into n where n is equals to the moles.
01:02
So, firstly we have to find out the moles of the propane.
01:06
So, moles of propane is equals to the mass of propane divided by the molar mass of the propane...