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Hello everyone.
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So in this given question we have a car which is in the parking mode and we have to push it to a distance of 10 meters, right? so we want to find we want to find out the work done in pushing the car.
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The coefficient of friction is given as one and the weight is 6 kilo needed.
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So here the approach to solve this question is we know that work is equals to force multiplied by the distance.
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Right? so we know the distance that it has to be moved by 10 meters.
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So we have to first find the force.
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So to find the force we have to make a free body diagram.
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So if this is the car, it has force acting as mg, which is 6 kilo newton.
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Right.
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It has a normal force, right? and it has a friction which is opposing.
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The motion right so we know that friction is given by mu into n right and when we balance the vertical forces we can see that n is equal to m g which is 6 kiloons right so we can substitute the value of mu and n in this equation so we get the frictional forces 1 multiplied by 6 kiloons right so we get that the frictional force is 6 kilo...