00:01
We are dealing with circularly polarized electromagnetic waves.
00:06
So for part a, we want the angle of refraction.
00:12
So we have tangent is equal to nb divided by n .a, which is 1 .62 divided by 1 .0, which gives you 1 .62.
00:26
So then that is equal to 58 .31 degrees.
00:31
Now we use snell's law 1 .00 times sign of 58 .31 degrees is equal to 1 .62 times sign and that'll be 31 .7 degrees.
00:51
For part b, we want the reflected intensity.
00:59
So we have e, r -e -f -l, so for reflective, and then e, i -n -c, and then y it's equal to sign divided by plus b which is equal to sign of 58 .32 minus 31 .7 and then this is sign 58 .32 plus 31 .7 and that gives you 0 .448 .48 .48 .448.
01:44
Then if we have i .r .e .f .l which is reflection.
01:51
We get 0 .104 i and c is equal to 0 .104 times 150 and that gives you 15 .1.
02:10
We're going to do c and d together.
02:16
So we have i -r -e -f is equal to i -i -n -c is equal to i -i -n -c, minus i -r -e -f -l, which is equal to 150 minus 15 .1...