00:01
So, given in the question, the total length of the copper wire that would be represented by capital l is given to be 3 .00 meters at t equal to 20 degree centigrade.
00:20
The copper wire has two sections of different lengths and diameters.
00:30
First section is of length l1 that is equal to 1 .20 meters and has a diameter d1 that is equal to 1 .20 mm.
00:46
The second section has length l2 equal to 1 .80 meters and has a diameter d2 that is 0 .60 mm.
00:58
The current in the l1 section of the copper wire is given to be i1 that is equal to 2 .0 milliampere.
01:10
It has been asked to find in part a, the current in the 0 .60 mm diameter section that is the current in the section of length l2.
01:26
In part b, the magnitude of electric field in the 1 .20 mm diameter section and in part c, the magnitude of the electric field e in the 0 .60 mm diameter section.
01:48
In part d, the potential difference between the ends of the 3 .00 meter length of the wire.
02:04
So coming to part a, the current through the entire length of the copper wire will remain the same irrespective of its diameter or area of cross section along its sections.
02:26
It is given in the question that the current in the l1 section having a diameter of 1 .20 mm is i1 that is 2 .0 milliampere.
02:41
So the current in the 0 .60 mm diameter section will be the same as the current in the 1 .20 mm diameter section that is i1 which is 2 .0 milliampere.
02:57
So this will be equal to the current in the 0 .60 mm diameter section would be 2 .00 milliampere...