a long cylindrical rod of diameter 200 mm with thermal conductivity of 05 wmk experiences unifor

A long cylindrical rod of diameter 200 mm with thermal...

A long cylindrical rod of diameter 200 mm with a thermal conductivity of 0.5 W/m·K experiences uniform volumetric heat generation of 24,000 W/m³. The rod is encapsulated by a circular sleeve having an outer diameter of 400 mm and a thermal conductivity of 4 W/m·K. The outer surface of the sleeve is exposed to cross-flow air at 27°C with a convection coefficient of 25 W/m²·K. (a) Find the temperature at the interface between the rod and sleeve and on the outer surface. (b) What is the temperature at the center of the rod?

Transcript

00:01 Hello in this question we have to find the temperature at the interface between the road and the sleeve and on the outer surface.

00:08 And for the second one, what is the temperature at the center road here? so as here in this question, as we know that re is equals to r -d divided by complete term with mew here at 27 degree centigrade here.

00:21 This one is heat transfer of the outer layer surface here.

00:24 So this one equals to as here rho equals to 1 .174 into 5 into 4.

00:30 Hundred into 10 rest to the power minus 3 here divided by complete term with 1 .859 into 10 as to the power 5 here this one is value of mu this one is value of row here v equals to 5 and d equals to 400 into 10 less to the power minus 3 here by simplifying these expression we can write it as 1 ,106 ,304 here now calculate the here predental number pr is equals to here we divided by alpha here which is equal to 1 .583 into 10 rest to the power minus 5 divided by complete term with alpha which is equal to 2 .25 divided into 10 rest to the power minus 5 here so by simplifying this expression this one equals to 07038 here with a relation suitable to the real the number occur here calculating an u number using standard relation here so n u is equal to here, nusinal number nu is equals to h0 d not divided by k not here.

01:38 So as here t not, since the inner surface t0 equals to t1 plus qr1 squared divided by complete term with 4k1 here.

01:47 So since q is equals to t1 minus of t not divided by complete term with r, slave minus of r, convert here.

02:02 So by simplifying this expression here to calculate td state rate as follows scenes, q is equals to pi r1 squared lq here which is equals to pi into 200 by 2 into 10 rest to the power minus 3 square here into 1 into 24 ,000 w here by simplifying this this one equals to 5753 .982 watt here.

02:32 This one is value of q here.

02:34 So calculate the rest tense here as our sleeve is equals to log of r2 by r1 divided by complete term with 2 pi k2 into l here which is equals to here ln of 200 divided by 100 divided by complete term with 2 pi into 4 into 1 here which is equals to 028c per w here or calculate here the temperature t1 since t1 is equal to here q into q equals to 753 into .982 into 0 .08 plus of 0 .032 plus of 27 here...

Question

Please give Ace some feedback