A long-jumper leaves the ground at an angle of 20° above the horizontal at a speed of 11 m/s. 1. How far does he jump in the horizontal direction? 2. What is the maximum height reached?
Added by Alicia J.
Step 1
To find the horizontal distance, we need to find the horizontal component of the velocity and the time of flight. The horizontal component of the velocity (v_x) can be found using the formula: v_x = v * cos(θ) where v is the initial velocity (11 m/s) and θ is Show more…
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Instruction: Answer the problem below using the kinematic equations for projectile motion. A long-jumper leaves the ground at an angle of 20° above the horizontal at a speed of 11 m/s. (a) How far does he jump in the horizontal direction? (b) What is the maximum height reached?
Shaiju T.
A long jumper leaves the ground at an angle of 20 degrees above the horizontal, at a speed of 11 m/s. The height of the jumper can be modeled by h(x) = -0.046x^2 + 0.364x, where h is the jumper's height in meters and x is the horizontal distance from the point of launch. A) At what horizontal distance from the point of launch does the maximum height occur? Please help me round to 2 decimal places. B) What is the maximum height of the long jumper? Please help me round to 2 decimal places. C) What is the length of the jump? Please help me round to 1 decimal place.
Donna D.
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