00:01
Shown here is the given figure from the problem.
00:03
The problem want us to determine the heat per second that flows from the boiling water to the ice water mixture and the length of the steel section.
00:16
So let's start with question a, which the flow per unit of time.
00:23
So we have q over t.
00:25
And this is equals to this equation.
00:30
The thermal conductivity multiplied by the area of the rod multiplied by the change in temperature over the length of the rod, which is in this case, we will use the copper since the length is given.
01:00
So we have, note that for the copper, the thermal conductivity is equals to 385 watts per nears.
01:13
Per kelvin and the area of the rod is 4 cm squared so it is 4 times 10 to negative 4 meter squared and the change in temperature here is from the boiling water to the junction so we have 100 degrees celsius minus 65 degrees of shoes over the given length of the copper which is 1 meter so solving we can find that the heat per second is 5.
01:46
39 joules per second...