00:01
Here we're going to be finding the total magnetic field due to two sources, one of which is a wire, so we'll need ampher's law, which you may use to find that the magnetic field due to a wire in its magnitude is a product of the fundamental constant permeability of free space, mu nod, times the current in the wire over 2 pi.
00:31
Times the distance from the wire.
00:35
The direction of that is a circle going around the direction of the wire, figured out by using your right hand, and we'll do that in a little bit.
00:49
But we need some points to find the total magnetic field, and we will have to use superposition.
00:57
That is the magnetic field total, total is a sum vector of the uniform b0 that points to the x plus the magnetic field of the wire.
01:15
And the direction of that magnetic field of the wire will depend on what position you're looking at.
01:22
So there are several positions that have been identified.
01:26
One is one meter away from the wire, which we put right down the y -axis going through.
01:33
The x -z plane at the origin.
01:38
The other one is one meter out along the x direction.
01:45
And finally, there is a point c in the negative c direction, 0 .25 meters behind what we're looking at in the negative c direction.
02:07
Okay, so we have two magnets.
02:09
To figure out for the b wire, but let's figure out the direction.
02:13
So the right -hand rule, usually what i do is i put my thumb in the direction of the current of my right hand, and then i see which way my fingers curl around the wire.
02:31
And so what i see is in the front on the z -axis, the wire is going back to the negative.
02:40
X.
02:42
On the other side, it's going to the positive x.
02:47
And it comes out in the z direction, in the front, and goes into the minus c back behind.
03:03
So that's going to be important when we think about those three points in the magnetic field of the wire.
03:09
So let's get to it.
03:12
For point a, we're going to figure out the magnitude of the b wire is mu -0, which is 4 pi times 10 to the minus 7, 8 constant, times the current, which, let's see, they give that as 8 amps.
03:42
I think i wrote that down.
03:49
Let's do that 8 amps.
03:55
So it's a substantial current...