09 m along the axis and above the center of the loop using the formula \(B = \frac{\mu_0 \cdot I \cdot r^2}{2(r^2 + x^2)^{3/2}}\).
Given:
\(\mu_0 = 4\pi \times 10^{-7} \, \text{T} \cdot \text{m/A}\),
\(I = 2 \, \text{A}\),
\(r = 0.4 \, \text{m}\),
\(x = 0.09 \,
Show more…