Question

A machine that produces ball bearings is set so that the average diameter is 0.53 inch. A sample of 10 ball bearings was measured with results shown below. 0.55 0. 49 0. 49 0.53 0.49 0.53 0.49 0.56 0.58 0.54 Assuming that the standard deviation is 0.05 inch, can we conclude at the 6% significance level that the mean diameter is different from 0.53 inch? a) State the null and alternate hypothesis. b) State the test statistics. c) State the p-value. d) What is your decision? e) Write a conclusion.

          A machine that produces ball bearings is set so that the average diameter is 0.53 inch. A sample of 10
ball bearings was measured with results shown below.
0.55 0. 49 0. 49 0.53 0.49
0.53 0.49 0.56 0.58 0.54
Assuming that the standard deviation is 0.05 inch, can we conclude at the 6% significance level that the
mean diameter is different from 0.53 inch?
a) State the null and alternate hypothesis.
b) State the test statistics.
c) State the p-value.
d) What is your decision?
e) Write a conclusion.
        
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Added by Christine S.

Elementary Statistics a Step by Step Approach
Elementary Statistics a Step by Step Approach
Allan G. Bluman 9th Edition
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A machine that produces ball bearings is set so that the average diameter is 0.53 inch. A sample of 10 ball bearings was measured with results shown below. 0.55 0. 49 0. 49 0.53 0.49 0.53 0.49 0.56 0.58 0.54 Assuming that the standard deviation is 0.05 inch, can we conclude at the 6% significance level that the mean diameter is different from 0.53 inch? a) State the null and alternate hypothesis. b) State the test statistics. c) State the p-value. d) What is your decision? e) Write a conclusion.
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Transcript

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00:01 In question it is given that null hypothesis mu that is equals to 0 .5 versus alternative hypothesis mu which is not equals to 0 .5 okay and that is a two tailed test that is a two tailed test so z value that is x bar minus mu divide sigma divide root under n so 0 .51 minus 0 .5 divide 0 .04 root under 25 which is equals to 1 .25 right so 1 .96 z is 1 .25 not in the rejection region rejection region is greater than 1 .96 right rejection…
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