A magnetic field has a magnitude of $0.078 \mathrm{T}$ and is uniform over a circular surface whose radius is $0.10 \mathrm{m}$. The field is oriented at an angle of $\phi=25^{\circ}$ with respect to the normal to the surface. What is the magnetic flux through the surface?
Added by Joel R.
Step 1
The area of a circle is given by $A=\pi r^2$, where $r$ is the radius. Plugging in the given values, we get: $$A=\pi (0.10 \mathrm{m})^2=0.0314 \mathrm{m}^2$$ Show more…
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