A manometer, containing a liquid with relative density of...

A manometer, containing a liquid with relative density of 13.6, has pressure readings, $p_1$ and $p_2$ as shown in Figure 3c. $h_1 = 400$ mm $p_1$ $p_2$ Figure 3c $h_2 = 300$ mm Datum If the pressure reading, $p_2$, is 20 kPa and the density of water, $ ho_{water}$, is 1,000 kg/m³, calculate: (i) the pressure reading, $p_1$, in kPa; and (5 marks) (ii) the height difference ($h_1 - h_2$) in mm if $p_1$ calculated in (i) is reduced by 10% while the pressure reading, $p_2$, remains at 20 kPa. (5 marks)

Transcript

00:01 Hello students in this question we are given a manometer who which contain a liquid having relative density 13 .6 and has pressure readings p1 and p2 so the value of p2 is equal to 20 kilo pascal and the height h1 is 400 millimeters which is so if we divide it by thousand so it would be 0 .4 meters and h2 is equal to 300 millimeters so if we divided by 1000 so we have 0 .3 meters this is h1 and h2 over here and we are given the density of water density of water which is equal to thousand kg per meter cube so we have to find the pressure reading p1 in kilopascal in the first part so let us see the diagram so over here this is the diagram and the first we have to find the pressure reading p1 in kilopascal now we know we can write from here that p1 plus so p1 plus row g delta h is equal to p2 we can write from the figure so here we have p1 plus row g delta h is h2 h1 minus h2 is equal to p2 so here we have p2 so here we have 1 equal to so p2 is 20 minus this term so density of water here is thousand multiply g is 9 .8 multiply by h1 is 0 .4 minus h2 0 .3 so here you have p1 equal to 190 to 0 pascal which will be equal to p1 will be equal to 19 .02 kilo this is the value of p1.

02:07 Now in the second part we have to find the height difference h1 minus h2 in millimeters if p1 calculated in part first is reduced by 10%.

02:17 So new value of p1 is 19 .02 minus 10 % that is 10 over 100 of 19 .02.

02:28 So here the value of p1 comes out to be.

02:33 So this is 17 .118 kilo pascal.

02:40 This is new value of p1 and it is saying that p2 remains the same.

02:45 So p2 is 20 kilo pascal.

02:50 P2 is 20 kilo pascal...

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