00:01
According to newton's second law of motion, net force on an object is equal to the product of its mass and acceleration.
00:07
Here we have m1 or mass 1, which is equal to 3 kilograms, is connected by a light string that passes over a pulley of mass 4 kilograms and has a radius of 25 centimeters and is connected to another mass, m2, which is 2 kilograms, that slides on a frictionless incline.
00:31
If there is no slippage between the string and the pulley, we want to find the angle or the acceleration of the mass m1.
00:42
So also given that the angle theta here, shown as the angle along the incline is 60 degrees, and that the moment of inertia i for the pulley is one half m times the square of the radius.
00:58
So what we will do first is to find or to draw the free body diagram for the masses.
01:07
So for m1 we have two forces acting along its direction of motion.
01:13
So by the way, the acceleration of m1 here will be downward.
01:19
And the forces that contributes to this acceleration are the tension force, p1, and the mass and rather the weight of m1, which is m1 times g so taking upward as the positive direction so we have the net force solved as t1 minus m1g and by newton cycle law this net force is equal to the product of the mass and the acceleration so since acceleration is going down in this case so that's going to be negative a 1 so this is t1 equals rearranging this equation we'll put everything uh will isolate t1 i put everything over to the other side then we get m1g minus m1a and let's call this as equation 1.
02:06
Next is mass 2.
02:11
So the forces on mass 2 along the direction of its motion which is parallel to the plane are tension 2 and the component of the weight that is perpendicular or rather that is parallel to the incline...