A mass m? = 0.50 kg hangs by a string, which is wound around a uniform cylindrical pulley of mass m? and radius R = 0.13 m. The hanging mass (m?) accelerates downward at a = 2.6 m/s² and the cylindrical pulley rotates about its center as the string unwinds (the string does not slip). The rotational inertia of a uniform cylinder of mass m and radius r rotating about an axis through its center (and perpendicular to the disk) is (1/2)mr². Ignore effects of friction and air resistance. What is the mass, m?, of the cylindrical pulley (in kg)?
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50 kg (mass hanging) m2 = mass of the pulley (unknown) g = 9.8 m/s^2 (acceleration due to gravity) R = 0.13 m (radius of the pulley) T = m1 * g (tension in the string) a = 2.6 m/s^2 (acceleration of the hanging mass) Show more…
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