A mass of 2kg is tied to the end of a string of length 1m. It is, then, whirled in a vertical circle with a constant speed of 5 ms-1. Given that g = 10 ms-2. At which of the following locations of tension in the string will be 70 N
Added by Barry B.
Step 1
Step 1: Calculate the centripetal force acting on the mass: Given: Mass (m) = 2 kg Velocity (v) = 5 m/s Radius (r) = 1 m Acceleration due to gravity (g) = 10 m/s^2 Centripetal force (Fc) = m * v^2 / r Fc = 2 * (5)^2 / 1 Fc = 2 * 25 Fc = 50 N Show more…
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