Question

A mass weighing $100 \mathrm{lb}$ (mass $m=3.125$ slugs in fps units) is attached to the end of a spring that is stretched 1 in. by a force of $100 \mathrm{lb}$. A force $F_{0} \cos \omega t$ acts on the mass. At what frequency (in hertz) will resonance oscillations occur? Neglect damping.

Name: A mass weighing 100 lb (mass m=3.125 slugs in fps units) is attached to the end of a spring that is stretched 1 in. by a force of 100 lb. A force F0cosω t acts on the mass. At what frequency (in hertz) will resonance oscillations occur? Neglect damping.
Uploaded: 2023-04-20T02:52:19-08:00
Duration: 1 min 42 s
Channel: Madhur L
Description: A mass weighing 100 lb (mass m=3.125 slugs in fps units) is attached to the end of a spring that is stretched 1 in. by a force of 100 lb. A force F0cosω t acts on the mass. At what frequency (in hertz) will resonance oscillations occur? Neglect damping.

          A mass weighing $100 \mathrm{lb}$ (mass $m=3.125$ slugs in fps units) is attached to the end of a spring that is stretched 1 in. by a force of $100 \mathrm{lb}$. A force $F_{0} \cos \omega t$ acts on the mass. At what frequency (in hertz) will resonance oscillations occur? Neglect damping.

Added by Steven T.

Differential Equations and Linear Algebra

Stephen W. Goode, Scott A. Annin 4th Edition

Instant Answer

Solved by Expert Madhur L

04/20/2023

Step 1

We know that the spring is stretched 1 in. by a force of 100 lb, so we can use Hooke's law: $$F = kx$$ where $F$ is the force, $k$ is the spring constant, and $x$ is the displacement from the equilibrium position. When $x = 1$ in. and $F = 100$ lb, we Show more…

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A mass weighing $100 \mathrm{lb}$ (mass $m=3.125$ slugs in fps units) is attached to the end of a spring that is stretched 1 in. by a force of $100 \mathrm{lb}$. A force $F_{0} \cos \omega t$ acts on the mass. At what frequency (in hertz) will resonance oscillations occur? Neglect damping.