A metal bar is used to conduct heat. When the temperature at one end is 100Ā°C and at the other is 40Ā°C, heat is transferred at a rate of 20 J/s. If the temperature of the hotter end is reduced to 70Ā°C, what will be the rate of heat transfer?
Added by Savisesh R.
Step 1
We know that the rate of heat transfer is proportional to the temperature difference between the two ends of the metal bar. We can write this as: Rate of heat transfer ā (Temperature difference) Show moreā¦
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How much heat does 25 g of a metal give off as it cools from 100 ${ }^{\circ} \mathrm{C}$ to $20^{\circ} \mathrm{C}$ if $c=880 \mathrm{~J} / \mathrm{kg} \cdot{ }^{\circ} \mathrm{C}$. $\Delta Q=m c \Delta T=(0.025 \mathrm{~kg})\left(880 \mathrm{~J} / \mathrm{kg} \cdot{ }^{\circ} \mathrm{C}\right)\left(-80{ }^{\circ} \mathrm{C}\right)=-1.76 \mathrm{~kJ}$ or to two significant figures, $-1.8 \mathrm{~kJ}$.
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