00:01
In this question, we are given that number of moles of carbon monoxide is equal to 0 .50, while number of moles of bromine is equal to 0 .400 and they are mixed in a container with a volume 1 .000000 litre and they are allowed to come at equilibrium, where equilibrium concentration of cobr2 is equals to 0 .233 molar.
00:35
And we have to find out the value of kc.
00:40
Now, kc, that is equilibrium constant, is equals to concentration of product divided by concentration of reactor.
00:50
So, to find out the value of kc, we will write, or we will draw the ice table for the reaction co plus br2 which are a reactant, they will react to foam co br2.
01:06
Ice table that is initial concentration in molar, concentration used to attain equilibrium concentration and then finally equilibrium concentration.
01:18
Initially carbon monoxide number of moles is 0 .50 molar.
01:24
Then its concentration would be number of moles divided by, that is 0 .5 .00 divided by volume, 1 litre.
01:34
Similarly, initial concentration for bromide would be 0 .4 .00 divided by 1.
01:41
And for cobr 2, it would be 0 since it is product and initially only reactant is given.
01:49
Now, concentration used to attain equilibrium concentration in case of c.
01:54
Let it's x and since it is used it would be minus x and in bromine it would also minus x but for cobr2 it would be plus x since products are formed in a reaction...