Question

A mixture of 22.0 g of P and 80.0 g of Cl2 reacts completely to form PCl3 and PCl5 as the only products. Find the mass of PCl3 that forms.

          A mixture of 22.0 g of P and
80.0 g of Cl2 reacts completely to
form PCl3 and PCl5 as the only products.
Find the mass of PCl3 that forms.
        

Added by Johnathan M.

Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
AceChat toggle button
Close icon
Ace pointing down

Please give Ace some feedback

Your feedback will help us improve your experience

Thumb up icon Thumb down icon
Thanks for your feedback!
Profile picture
A mixture of 22.0 g of P and 80.0 g of Cl2 reacts completely to form PCl3 and PCl5 as the only products. Find the mass of PCl3 that forms.
Close icon
Play audio
Feedback
Powered by NumerAI
David Collins Jennifer Stoner
Ivan Kochetkov verified

Susan Hallstrom and 92 other subject Chemistry 101 educators are ready to help you.

Ask a new question

*

Labs

-

Want to see this concept in action?

NEW

Explore this concept interactively to see how it behaves as you change inputs.

View Labs

*

Key Concepts

-
Key Concept
Premium Feature
Explore the core concept behind this problem.
Play button
Key Concept
Premium Feature
Explore the core concept behind this problem.
Your browser does not support the video tag.

*

Recommended Videos

-
a-mixture-of-206-g-of-p-and-794-g-cl2-reacts-completely-to-form-pcl3-and-pcl5-which-are-the-only-products-determine-the-mass-of-pcl3-that-forms-5

A mixture of 20.6 g of P and 79.4 g Cl2 reacts completely to form PCl3 and PCl5, which are the only products. Determine the mass of PCl3 that forms

Syon S.

a-mixture-of-206-g-of-p-and-794-g-cl2-reacts-completely-to-form-pcl3-and-pcl5-which-are-the-only-products-determine-the-mass-of-pcl3-that-forms-3

A mixture of 20.6 g of P and 79.4 g Cl2 reacts completely to form PCl3 and PCl5, which are the only products. Determine the mass of PCl3 that forms.

Dominique Jan T.

a-mixture-of-1818-g-of-cl2-and-397-g-of-p-reacts-completely-to-form-pcl3-and-pcl5-find-the-mass-of-pcl5-produced-i-really-need-help-with-this-question-please-49683

A mixture of 181.8 g of Cl2 and 39.7 g of P reacts completely to form PCl3 and PCl5. Find the mass of PCl5 produced.

Sima S.


*

Recommended Textbooks

-
Chemistry: Structure and Properties

Chemistry: Structure and Properties

Nivaldo Tro 2nd Edition
achievement 1,177 solutions
Chemistry The Central Science

Chemistry The Central Science

Theodore L. Brown 14th Edition
achievement 1,041 solutions
Chemistry

Chemistry

Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste 10th Edition
achievement 1,397 solutions

*

Transcript

-
00:04 We are told we have a mixture of p and cl2, and it forms p, c, l3, and p .l5.
00:25 Find the mass of pcl3.
00:34 I am not sure i can do this one.
00:59 Okay, maybe i can.
01:04 So i have p plus c02, and they're performing these two, or producing those two products, and i can balance it just like this, so i think i've got it here.
01:16 We'll see.
01:19 We're given 22 .0 grams of p and we're given 80 .0 grams of cl2.
01:30 We're asked to find the mass of plc that forms.
01:44 So we're asked to find the mass of that substance that's produced.
01:52 Let us begin our calculations.
01:57 So chlorine is 70 .91 and phosphorus, this is 30 .97, i think.
02:11 Yes.
02:33 Then i need next, my molar mass of p -c -l -3.
02:40 That will be 137 .33.
02:57 Let me do this math.
02:58 22 times 137 .33 divide 30 .97 .97 .97 .97 .97 .97 .97 .97 .97 .97.
03:09 97.
03:09 97...
Need help? Use Ace
Ace is your personal tutor. It breaks down any question with clear steps so you can learn.
Start Using Ace
Ace is your personal tutor for learning
Step-by-step explanations
Instant summaries
Summarize YouTube videos
Understand textbook images or PDFs
Study tools like quizzes and flashcards
Listen to your notes as a podcast
Continue solving this problem
Create a free account to:
  • View full step-by-step solution
  • Ask follow-up questions with Ace AI
  • Save progress and study later
Continue Free
Join the community

18,000,000+

Students on Numerade


Trusted by students at 8,000+ universities

Numerade

Get step-by-step video solution
from top educators

Continue with Clever
or



By creating an account, you agree to the Terms of Service and Privacy Policy
Already have an account? Log In

A free answer
just for you

Watch the video solution with this free unlock.

Numerade

Log in to watch this video
...and 100,000,000 more!


EMAIL

PASSWORD

OR
Continue with Clever