A mixture of gases at a pressure of 1.01 x 10^5 Nm^-2 has volume compositions of 30% CO, 50% O2, 20% CO2. What is the partial pressure of each gas?

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So here we have a mixture of gases. The total pressure is going to be equal to 1.01 times 10 to the fifth, and this would be newton's per meter square or we could say pascal's as the s i unit for pressure, and we have 30 percent carbon oxide, 50 percent oxygen and 20 percent carbon Dioxide and so we can find the partial pressure of carbon monoxide by taking the mole fraction, which in this case is the volume fraction multiplied by the total pressure. So the partial pressure for carbon monoxide is going to be equal to .3 multiplied by 1.01 times 10. To the fifth newton per meter squared- or we can say 3.03 times, 10 to the 4 pascal's and the pattern continues, so the partial pressure of o 2 would be equaling 2.5 times the total pressure 5.05 times 10 to the fourth pascal's, and we have the partial Pressure of carbon dioxide- and this would be .2 times the total pressure so again, 2.02 times 10 to the 4 pascal's. That is the end of the soluti.

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