A model rocket rises with constant acceleration to a height of 3.8 m m , at which point its speed is 27.0 m/s m / s . Find the height of the rocket 0.20 s after launch. Find the speed of the rocket 0.20 s after launch.
Added by Joaquin L.
Step 1
Given: Initial velocity (u) = 0 m/s, final velocity (v) = 27 m/s, height (h) = 3.8 m Use the equation \(a = \frac{v^2 - u^2}{2h}\) Substitute the values: \(a = \frac{27^2 - 0^2}{2*3.8} = \frac{729}{7.6} = 95.9 \, m/s^2\) Show more…
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