00:01
What should be the moment of inertia of our flywheel? we're given our number of load speed to be equal to 600 rpm.
00:12
We're also given, from this we can use, we can find omega nl, which is 2 pi nl divided by 60, or 2 pi, excuse me, 2 pi times 600 divided by 60, which is 62 .8 radiance per second.
00:30
Our slip is 0 .08, and our speed of our torque at 500 nanometers, omega is equal to 1 minus 5, or 1 minus 8, 0 .08, which is our slip, times 20 times pi, which is 57 .7 radiance per second.
00:56
So using our given data, t is 500 nuten meters, our t -h is 580 .5 .5 .5 .5 .5 .0 meters.
01:03
About 10 seconds...