00:02
Hi, in this question we are asked to calculate the concentration of sodium sulphate in mole per liter.
00:08
Mularity is used to express the concentration in mole per liter which is equals to moles of salute divided by volume of solution in liters, which is further equals to mass of salute divided by molecular weight of salute multiplied by volume of solution in liter.
00:49
Since we are given with concentration of salute, that is 1 ,000 ppm.
01:00
1000 ppm means there are 1 ,000 milligram of salute present in 1 liter of solution and here density is given 1 grams per liter so we can convert this in the grams also that is 1 grams of salute divided by 1 liter of solution.
01:36
By putting the value of density, we can say that 1 grams of salute present in 1 kg of solution.
01:59
So we get all the information now we can put the values in the above formula of molarity.
02:12
Equals to the mass of salute is 1 gram.
02:16
Molecular weight of sodium sulfate is 142 grams per more.
02:24
Multiply by the volume that is 1 litre.
02:28
On calculating, we will get the concentration value that is equals to 7 .04 into 10 raise to power minus 4 .4 .5 .4.
02:44
Molar or we can write it as 7 .04 into 10 raise to power minus 4 mole per liter.
02:56
This question contained two parts...