00:01
Hi there, so for this problem we are told that a naked downception in a pie float called a venturi develops a low throat pressure which can aspire fluid upward from the reservoir, as is shown in this figure.
00:18
Now, using bernoulli's equation with no loses, we need to derive an expression of the velocity b1, which is just sufficient to bring reservoir fluid into the throat.
00:35
Now, with that said, we know that in this case, water will begin to aspirate into the throat when the pressure at the point a at this point minus the pressure at the point one is equal to the density times the acceleration due to gravity, times the height h.
01:06
Hence, the volume flow b1 is going to be the volume 2 times the diameter 2 divided by the diameter 1, and that to the square.
01:23
Now, bernoulli's equation when the difference in seed is equal to 0, we will obtain that this is the pressure 1 plus 1 divided by 2 times the density times the speed 1 squared.
01:43
And this can be approximate to the atmospheric pressure plus 1 divided by 2 times the volume 2 square.
01:58
Now, what we need to do in this case is to solve for the pressure a minus the pressure 1, which we can write to be equal to the density divided by 2, this times alpha to the square minus 1, this times the speed at the point to square...