00:01
Hi students in this question, a negatively charged particle minus q is been given, which is moving towards the positive x -axis with a velocity vector v.
00:10
On the other hand, the magnetic field experienced by this charge is taken as minus b, which is acting towards the positive y -axis.
00:18
Now in this question, we are asked to find out the direction of force vector f acting on this particular charge, where the direction of force can be found out using the lawrence -pulse equation which is given as vector f to be equal to q into vector v cross vector b.
00:39
Now from this equation, it is clear that the direction of the force is been obtained by the cross product value of this velocity as well as magnetic field.
00:49
Now in this case, you can see that this velocity is acting towards the positive x -axis while the magnetic field is acting towards the positive y -axis.
00:58
Therefore, the angle between this velocity as well as magnetic field is taken to be 90 degrees.
01:04
Therefore, our laurent force equation changes as vector f to be equal to qv vector into b vector into sine 90 degree...