00:01
Hi, from the question, given that f of t is equal to 20 divided by 1 plus 125 e to the power of minus 0 .60.
00:20
So in part a, we need to find f of 9.
00:26
So, f of 9 is equal to 20 divided by 1 plus 125e to 1 plus 125e to the power of 5.
00:36
Of minus 0 .6 times of 9 which is equal to 12 .783.
00:44
Hence we conclude that f of 9 is equal to 12 .783 thousand people.
01:02
Now let us move on to part two.
01:06
So part two we need to find derivative of f of t that is f dash of t.
01:13
So, so this is equal to d by dt of 20 divided by 1 plus 125 e to the power of minus 0 .60.
01:27
Now let us find the derivative.
01:32
So this will be equal to minus 1 times of 1 plus 125e to the power of minus 0 .60.
01:42
The old power minus 1 minus 1 is minus 2 times here 20 is remains constant times now differentiate the inner terms so 125 times minus 0 .6 e to the power of minus 0 .6 t so simplify further we obtain the value of f dash of t is equal to 1500 e to the power of minus 0 .60 divided by 1 plus 125 e to the power of minus 0 .6 t.
02:34
Now let us, this is old square.
02:37
Now let us move on to the part c.
02:40
So part c we need to find the rate after 11 days.
02:45
So we need to find f dash of 11.
02:48
F dash of 11 is equal to substitute the value of tz equal to 11.
02:54
So ,000 500 e to the power of minus 0 .6 times of 11 divided by 1 plus 125e to the power of minus 0 .6 times of 11 the old square...