A newspaper article reported the results of a study comparing the proportions experiencing pain relief using a new medication compared to using a placebo. The study showed that the proportion experiencing pain relief was higher for the new medication (p1) when compared to the placebo (p2). The researcher is quoted as saying that there was less than a 1 in 100 probability that the observed differences in proportions was due to chance. The null hypothesis for this study is: Group of answer choices Ho: p1 – p2 = 0 Ho: p1 - p2 > 0 Ho: p = 0 Ho: p1 - p2 NE 0
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The study is comparing two proportions: the proportion of patients experiencing pain relief using a new medication (p1) and the proportion using a placebo (p2). The claim is that the new medication is more effective than the placebo, which suggests that p1 is Show more…
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A newspaper article reported the results of a study comparing the proportions experiencing pain relief using a new medication compared to using a placebo. The study showed that the proportion experiencing pain relief was higher for the new medication when compared to the placebo. The researcher is quoted as saying that there was less than a one in 100 probability that the observed differences in proportions was due to chance. In statistical terms, the research was saying that the results are: not statistically significant at the .01 level of significance probably due to sampling error probably due to chance statistically significant at the .01 level of significance
Thuc N.
An article reported the results of a study comparing the proportion still experiencing pain using a new medication (p1) compared to an older medication (p2). The expectation of the study was that the proportion still experiencing pain would be lower with the new medication. The study showed that the proportion still experiencing pain was lower for the new medication (p1) when compared to the old medication (p2). The researcher is quoted as saying that there was less than a 5 in 100 probability that the observed differences in proportions were due to chance. In statistical terms, the researcher was saying the results of the study are: Group of answer choices a: Statistically significant at the .05 level of significance. b: Not statistically significant at the .05 level of significance. c: Probably due to sampling error. d: Statistically significant at the .01 level of significance.
Sri K.
4. A researcher compared pulse rates of identical twins to see whether there are any differences. The researcher randomly selected five sets of twins. Differences in each set of twin set was determined: 7, 3, 5, 1, 4 (a) Calculate the mean of these differences. Include units in your final answer. SHOW WORK (b) Calculate the standard deviation of these differences rounded to one decimal place. Include units in your final answer. SHOW WORK (c) From the scenario described above, what is the experimental design used in this one sample t test of significance that asks: is there evidence identical twins have different pulse rates? (d) State the hypotheses using mathematical notation in the test of significance described in part (c). (You do not need to carry out this test of significance, just state the hypotheses.) 5. Exam scores from a random sample of 12 students in a class is selected. Their exam scores are recorded in the following table: (a) Create a stem plot of their study hours recorded above. (b) From your stem plot above, explain if it is or is not safe to use a t-procedure to analyze these data.
Adi S.
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