Question

A newspaper reported on the results of an opinion poll in which adults were asked what one thing they are most likely to do when they are home sick with a cold or the flu. In the survey, 65% said that they are most likely to sleep and 15% said that they would watch television. Although the sample size was not reported, typically opinion polls include approximately 1,000 randomly selected respondents. a. Assuming a sample size of 1,000 for this poll, construct a 90% confidence interval for the true percentage of all adults who would choose to sleep when they are at home sick. The 90% confidence interval is (\boxed{\quad}, \boxed{\quad}). (Round to the nearest hundredth as needed.) b. If the true percentage of adults who would choose to sleep when they are at home sick is 73%, would you be surprised? O No O Yes

          A newspaper reported on the results of an opinion poll in which adults were asked what one thing they are most likely to do when they are home sick with a cold or the flu. In the survey, 65% said that they are most likely to sleep and 15% said that they would watch television. Although the sample size was not reported, typically opinion polls include approximately 1,000 randomly selected respondents.
a. Assuming a sample size of 1,000 for this poll, construct a 90% confidence interval for the true percentage of all adults who would choose to sleep when they are at home sick.
The 90% confidence interval is (\boxed{\quad}, \boxed{\quad}).
(Round to the nearest hundredth as needed.)
b. If the true percentage of adults who would choose to sleep when they are at home sick is 73%, would you be surprised?
O No
O Yes

$A newspaper reported on the results of an opinion poll in which adults were asked what one thing they are most likely to do when they are home sick with a cold or the flu. In the survey, 65% said that they are most likely to sleep and 15% said that they would watch television. Although the sample size was not reported, typically opinion polls include approximately 1,000 randomly selected respondents. a. Assuming a sample size of 1,000 for this poll, construct a 90% confidence interval for the true percentage of all adults who would choose to sleep when they are at home sick. The 90% confidence interval is (\boxed{\quad}, \boxed{\quad}). (Round to the nearest hundredth as needed.) b. If the true percentage of adults who would choose to sleep when they are at home sick is 73%, would you be surprised? O No O Yes$

Added by Austin M.

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