00:01
Hello students, in the question we are given a solenoid made up of copper wire.
00:06
We have length of copper wire it is equal to 10 meters, diameter it is equal to 1 .0 into 10 to the power minus 3 meters.
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We have resistance equal to 0 .005 ohms per 0 .5 meters length of wire.
00:24
We have radius of solenoid equal to 2 .0 centimeter.
00:29
We can convert this into meters so we get 0 .02 meters.
00:35
Here for part a we have formula resistance it is equal to resistivity rho length divided by area of cross section.
00:45
Here we have resistance 0 .005 ohms it is equal to resistivity rho length of wire corresponding to resistance it is 0 .5 meters divided by area of cross section.
00:58
Now resistance for entire length of wire that is denoted by r2 it is equal to rho.
01:06
The resistivity it would remain same because same material it is being used into length that is entire length of wire that is 10 meters divided by area of cross section a.
01:20
Area of cross section it would remain same again because same thickness of wire is being used.
01:26
Here we can write r2 divided by 0 .005 this is equal to rho times 10 divided by a divided by rho times 0 .5 divided by a.
01:39
This comes out to be equal to 10 divided by 0 .5.
01:43
From here we get r2 it is equal to 10 divided by 0 .5 into 0 .005 ohms this comes out to be equal to 0 .1 ohm.
01:58
So we have the resistance of 10 meter length of wire or resistance of solenoid it is equal to 0 .1 ohm...