00:01
The sound level in terms of decibel is solved as follows.
00:04
Beta, which is the sound level in decibel, equals 10 times log to the base 10 of i, where i is the intensity, all over 10 to the negative 12.
00:14
In this problem, we're given with a noisy machine that produces 80 decibel.
00:19
Let us an 80 decibel sound rating.
00:22
We want to find the number of machines that we could add to the factory so that the noise level, would not exceed beyond 90 decibel which is the limit set by the federal regulations.
00:39
So we assume that the machines are identical so that they produce the same amount of sound intensity.
00:47
So first is that we will find the intensity corresponding to sound level of 80 decibels.
00:54
So from that we will plug into our beta, the value 80.
00:59
And we will solve for the i in this case.
01:05
So we have to divide both sides by 10, so we will get 8 equals log to the base 10 of i over 10 to the negative 12...